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April 1, 2015

April 1, 2015

Posted by **hurry! nick** on Monday, May 6, 2013 at 8:05am.

- hurry! math -
**Steve**, Monday, May 6, 2013 at 10:43am125^x-2 = 125^2 * 125^x-4

125^x-3 = 125 * 125^x-4

so, what we have is

125^x-4 (125^2 - 125) = 125^x-4

125^2 - 125 = 1

No solution

Evidently I misunderstood the notation. If you meant

125^x - 2 + 125^x - 3 = 125^x - 4

125^x = 1

x = 0

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