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hurry! math

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Find the value of x in 125^x-2 + 125^x-3 = 125^x-4.with explanation

  • hurry! math - ,

    125^x-2 = 125^2 * 125^x-4
    125^x-3 = 125 * 125^x-4
    so, what we have is

    125^x-4 (125^2 - 125) = 125^x-4
    125^2 - 125 = 1
    No solution

    Evidently I misunderstood the notation. If you meant

    125^x - 2 + 125^x - 3 = 125^x - 4
    125^x = 1
    x = 0

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