Friday

November 28, 2014

November 28, 2014

Posted by **Maureen** on Monday, May 6, 2013 at 5:38am.

(i) All 3 are defective

(ii) All 3 are good

(iii) The first selected is defective

(iv) 1 defective and 2 good

(v) 2 defective and 1 good

(vi) At most 2 are good

- Math -
**PsyDAG**, Monday, May 6, 2013 at 1:38pmIf the events are independent, the probability of both/all events occurring is determined by multiplying the probabilities of the individual events.

1. (1/5)^3 = ?

2. (4/5)^3 = ?

3. 1/5

4. 1/5 * 4/5 * 4/5 = ?

5. You do it, using similar process.

6. This is none good, one good*or*2 good.

Either-or probabilities are found by adding the individual probabilities.

**Answer this Question**

**Related Questions**

math - A manufacturer of light bulbs knows that 3% of the production of their ...

math - A manufacturer of light bulbs knows that 3% of the production of their ...

Math - In a shipment of 1000 light bulbs 1/40 of the bulbds were defective. What...

Maths - In a large lot of electric light bulbs,5% of the bulbs are defective....

Probability Math - Through a mix up on the production line, 5 defective light ...

math - A box contain 12 cell phones of which 4 are defective.all phones look ...

algebra 1 - From a shipment of 350 light-bulbs, a sample of 70 was selected at ...

finite math - a quality control engineer at a light bulb plant estimated that 1...

finite math - a quality control engineer at a light bulb plant estimated that 1...

Math - In one hour, a factory packaged 150 boxes of light bulbs. Estimate the ...