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March 28, 2015

March 28, 2015

Posted by **Mathslover Please help** on Sunday, May 5, 2013 at 11:37pm.

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**Anonymous**, Monday, May 6, 2013 at 5:22pm10

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**a**, Monday, May 6, 2013 at 10:58pmwrong

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**dr. cao**, Monday, May 6, 2013 at 11:34pmshould be 26

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**hans**, Tuesday, May 7, 2013 at 12:46amWRONG!!!

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**dr.cao 2nd**, Tuesday, May 7, 2013 at 1:32amwrong dr.cao.....

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**dr.cao 3rd**, Tuesday, May 7, 2013 at 1:33amwrong de.cao

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**dr.cao 3rd**, Tuesday, May 7, 2013 at 1:34amwrong dr.cao.....

wrong dr.cao.....

wrong dr.cao.....

wrong dr.cao.....

wrong dr.cao.....

wrong dr.cao.....

wrong dr.cao.....

wrong dr.cao.....

wrong dr.cao.....

wrong dr.cao.....

wrong dr.cao.....

wrong dr.cao.....

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**dr.cao 2nd**, Tuesday, May 7, 2013 at 1:39amcalm down dr.cao 3rd

calm down

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**Mathslover Please help**, Tuesday, May 7, 2013 at 2:02amDude don`t fight please tell the answer

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**Athul**, Tuesday, May 7, 2013 at 12:49pm50

Let the radius of larger circle be a, smaller ones be 'b' and 'c'.

Ans = pie(a^2-(b^2+c^2)) here we are only concerned with (a^2-(b^2+c^2))=

(a^2 - ((b + c)^2 - 2bc) = 2bc as a=b+c

Using intersecting chord theorem,

2bc= AC*BC/4= PC*CQ/4= 10*10/4 as diameter bisects chord

= 50 Ans

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**Athul**, Tuesday, May 7, 2013 at 8:08pmSORRY GUYS I MEANT TO SAY ITS 60 SORRY DONT USE 50 ITS 60!!

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