Posted by **Jo-Anne** on Sunday, May 5, 2013 at 7:27pm.

The construction of the regular pentagon is equivalent to the construction of the point in the unit circle with x coordinate x1 = the square root of 5 - 1 divided by 4. Use this to construct a regular pentagon that has all its vertices inside the unit circle. Write a construction protocol and justify all your construction steps. How do I construct the square root of 5-1?

- geometry -
**Reiny**, Sunday, May 5, 2013 at 7:55pm
You must mean

√5 - 1

draw a square ABCD with sides 2 , where A and B are the endpoints of the base

Extend the length of the base to the right

Draw a vertical MN where M is the midpoint of AB and N is the midpoint of CD

You should see a right-angled triangle with legs AB = 1 and MN = 2

by Pythagoras AN = √5

Use your compass, centre at A and radius AN , draw an arc to cut the entension of AB at P

so AP = √5

and MP = √5 - 1

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