Thursday

July 24, 2014

July 24, 2014

Posted by **Megan** on Sunday, May 5, 2013 at 5:22pm.

A) She uses a previous estimate of 0.48?

B) She does not use any prior estimates?

Please help!!!!!!!!!!

- Statistics -
**MathGuru**, Sunday, May 5, 2013 at 5:32pmFormula to find sample size:

n = [(z-value)^2 * p * q]/E^2

... where n = sample size, z-value is found using a z-table for 90% confidence (which is 1.645), p = .48 (when no value is stated in the problem p = .50), q = 1 - p, ^2 means squared, * means to multiply, and E = .02.

Plug values into the formula and calculate n.

I hope this will help get you started.

- Statistics -
**Megan**, Sunday, May 5, 2013 at 5:39pmTHANK YOU

- Statistics -
**Megan**, Sunday, May 5, 2013 at 5:48pmTHANK YOU

- Statistics -
**Anonymous**, Tuesday, May 6, 2014 at 12:45pmA researcher wishes to estimate the proportion of adults who have high-spped internet access. What size sample should be obtained if she wishes the estimate to be within 1% of true proportion

- Statistics -
**v**, Saturday, July 12, 2014 at 7:11pmHow do you know what the z-value is? I've never used a z-table.

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