Posted by **Annointed Jesu** on Sunday, May 5, 2013 at 5:22am.

an object is thrown upward with an initial velocity 'u' m/s. derive an expression for the height 'h' at which its kinetic energy becomes equal to its potential energy.

- physics -
**Elena**, Sunday, May 5, 2013 at 8:44am
h=(u²- v²)/2g

v²=u²- 2gh,

KE=m•v²/2= m(u²- 2gh)/2,

KE=PE =>

m(u²- 2gh)/2 =mgh,

(u²- 2gh)/2= gh,

u²=4gh,

h= u²/4g.

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