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March 28, 2017

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the fictitious compound pandemonium carbonate has a ksg=3.091*10^-9 M 3 in water at poor temperature .calculate the solubility of PnCo3 in an aqueous solution of 1.11 M pandemonium sulfate.
express your answer in units of molarity.

  • chemistry - ,

    .......PnCO3 ==> Pn^2+ + CO3^2-
    I......solid.....1.11.....0
    C....x dissolves..x.......x
    E......solid......x.......x

    Ksp = (Pn^2+)(CO3^2-)
    3.091E-9 = (x+1.11)(x)
    Solve for x = solubility of PnCO3 in mols/L.

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