Posted by **Alaina** on Saturday, May 4, 2013 at 6:58pm.

calculate delta y for f(x)= x^(3/2) with x= 4 and delta x= dx=0.1

delta y= f(x+delta x)- f(x)

= f(4.1) - f(4)

delta y= f(4.1)-8

f(x + delta x)= 8 + 3/2*x^(1/2)*0.1

= 8 + 0.15x^(1/2)

= 8 + 0.30

= 8.30

delta y= 8.30 - 8

delta y= 0.30

but this is wrong. why is it wrong?

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