Wednesday

November 26, 2014

November 26, 2014

Posted by **justin** on Saturday, May 4, 2013 at 2:58pm.

C =

3t/26 + t^3

Use differentials to approximate the change in the concentration when t changes from

t = 1

to

t = 1.5.

(Round your answer to four decimal places.)

- math calculus -
**Steve**, Saturday, May 4, 2013 at 6:43pmC = 3t/26 + t^3

dC = (3/26 + 3t^2) dt

Just plug in t=1, dt=0.5

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