Thursday

July 31, 2014

July 31, 2014

Posted by **Anirudh Mahapatro** on Saturday, May 4, 2013 at 4:05am.

- math -
**Bosnian**, Saturday, May 4, 2013 at 5:00am6 x - 2 y = 2 Subtract 6 x to both sides

6 x - 2 y - 6 x = 2 - 6 x

- 2 y = 2 - 6 x Divide both sides by - 2

- 2 y / - 2 = 2 / - 2 - 6 x / - 2

y = - 1 + 3 x

y = 3 x - 1

Equations :

y = 3 x - 1 and 6 x - 2 y = 2 are same equation.

On interval 0 < = x < = 25 you have 26 integers :

0 = first integer

1 = second integer

2 = third integer

...

25 = twenty-sixth integer

You have 26 pairs of integers ( x , y ) which satisfied given conditions.

**Related Questions**

math - How many pairs of integers (x,y) satisfy the conditions y=3x−1, 6x...

Math - How many ordered pairs of integers (x,y) are there that satisfy |x|+|y|=...

algebra.. HELP ME!!! - How many pairs of integers (x,y) satisfy the conditions y...

Math (Algebra) - How many ordered pairs of integers (x,y) are there that satisfy...

Mayhs Please Help - How many pairs of positive integers (a,b), where a≤b ...

advanced functions/precalculus - 1. The function f(x) = (2x + 3)^7 is the ...

math - n and m are positive integers that satisfy n^3+2n^2=m^2. If 1≤n&#...

mathURGENT!!!!!!!!!! - find all ordered pairs of positive integers (x,y) that ...

Calculus - F (x ) = x^5 + 2x^3 + x − 1 a) What conditions must f (x ) ...

Number Theory.,Math - How many ordered pairs of positive integers (a,b) are ...