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December 21, 2014

December 21, 2014

Posted by **URGENT** on Friday, May 3, 2013 at 9:19pm.

when x<–3 and by the formula

f(x)=2x^2–4x+a

What value must be chosen for a in order to make this function continuous at -3?

- Math Calculus -
**Steve**, Saturday, May 4, 2013 at 4:49am6x^3+17x^2+4x+21 = (x+3)(6x^2-x+7)

so f(x) -> 64 as x -> -3

so, we want 2x^2-4x+a = 64 when x = -3

64 = 18+12+a

a = 34

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