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The function f is given by the formula f(x)=6x^3+17x^2+4x+21/x+3

when x<–3 and by the formula
What value must be chosen for a in order to make this function continuous at -3?

  • calculus -

    mmmh, took me a while to understand what the question is asking.

    First of all you will need brackets:
    f(x) = (6x^3+17x^2+4x+21)/(x+3)
    = (6x^2 - x + 7) , where x≠ -3
    = (x+1)(6x-7)

    we want this to be the same as
    2x^2 - 4x + a

    If 6x^2 - x + 7 = 2x^2 - 4x + a

    4x^2 + 3x + 7 = a

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