The function f is given by the formula f(x)=6x^3+17x^2+4x+21/x+3
when x<–3 and by the formula
What value must be chosen for a in order to make this function continuous at -3?
calculus - Reiny, Friday, May 3, 2013 at 10:51pm
mmmh, took me a while to understand what the question is asking.
First of all you will need brackets:
f(x) = (6x^3+17x^2+4x+21)/(x+3)
= (6x^2 - x + 7) , where x≠ -3
we want this to be the same as
2x^2 - 4x + a
If 6x^2 - x + 7 = 2x^2 - 4x + a
4x^2 + 3x + 7 = a