Wednesday

April 23, 2014

April 23, 2014

Posted by **Unknown** on Friday, May 3, 2013 at 9:17pm.

when x<–3 and by the formula

f(x)=2x^2–4x+a

What value must be chosen for a in order to make this function continuous at -3?

- calculus -
**Reiny**, Friday, May 3, 2013 at 10:51pmmmmh, took me a while to understand what the question is asking.

First of all you will need brackets:

f(x) = (6x^3+17x^2+4x+21)/(x+3)

= (6x^2 - x + 7) , where x≠ -3

= (x+1)(6x-7)

we want this to be the same as

2x^2 - 4x + a

If 6x^2 - x + 7 = 2x^2 - 4x + a

4x^2 + 3x + 7 = a

**Related Questions**

Math Calculus - The function f is given by the formula f(x)=6x^3+17x^2+4x+21/x+3...

polynomials - (3+7x)-(16x2+15x2) (3+1x)-(12x+16+0+18x2) Q4: (15+13x2+14x2)+(13x...

polynomials - (3+7x)-(16x2+15x2) (3+1x)-(12x+16+0+18x2) Q4: (15+13x2+14x2)+(13x...

Calculus - Use the algorithm for curve sketching to sketch the graph of each ...

Calculus - Given the function" f(x)=1/4x− 3, find a formula for the ...

algebra - Use the quadratic formula to find the zeros of the function. Round to ...

Algebra - (x)/(x-3)-4-(2x-5)/(x+2) I posted something before this, so now this ...

Algebra - (x)/(x-3)-4-(2x-5)/(x+2) I posted something before this, so now this ...

algebra - what is a quartic function with only the two real zeros given x=5 and ...

math-calculus - i think i do something wrong again(2x+1)/(x-3)-(4x-1)/(2x-3) = 0...