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Posted by on Friday, May 3, 2013 at 7:06pm.

A grindstone in the shape of a solid disk with diameter 0.520 and a mass of = 50.0 is rotating at = 860 . You press an ax against the rim with a normal force of = 250 (Figure 1) , and the grindstone comes to rest in 7.40 .
Find the coefficient of friction between the ax and the grindstone. You can ignore friction in the bearings.

  • physics - , Friday, May 3, 2013 at 7:49pm

    angular momentum initial = I omega
    I = (1/2) m r^2 = (1/2)(50).26^2
    860 what? rpm?
    860 rev/min * 1/60 min/sec * 2 pi radians/rev = 90 rad/sec
    so Iw= 152

    torque * time = change of angular momentum

    250 N * mu * 7.4 sec = 152

    I am just guessing at your units for everything

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