A nitric acid solution containing 71.0% by mass of the acid has a density of 1.42g/ml how many grams of nitric acid are present in 1.0L of this solution
mass=.71*1.42kg/L*1L
566
To find the number of grams of nitric acid present in 1.0 L of the solution, we need to use the given percentage by mass and density of the solution.
Here's how we can calculate it:
Step 1: Convert the density of the solution from grams per milliliter (g/mL) to grams per liter (g/L). Since there are 1000 mL in 1 L, we can multiply the density by 1000:
Density = 1.42 g/mL * 1000 mL/L = 1420 g/L
Step 2: Calculate the mass of the solution based on its density. We know that the mass of the solution is directly proportional to its density:
Mass of solution = Volume * Density
Since we have 1.0 L of the solution, we can calculate the mass of the solution:
Mass of solution = 1.0 L * 1420 g/L = 1420 g
Step 3: Determine the mass of the nitric acid in the solution using the given percentage by mass. The given percentage by mass is 71.0%. This means that 71.0 g of nitric acid is present in 100 g of the solution.
To calculate the mass of nitric acid in the solution:
Mass of nitric acid = (Percentage by mass / 100) * Mass of solution
Mass of nitric acid = (71.0 / 100) * 1420 g = 1006.2 g
Therefore, there are 1006.2 grams of nitric acid present in 1.0 L of the solution.