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March 29, 2015

March 29, 2015

Posted by **Lynn** on Friday, May 3, 2013 at 12:55pm.

write an equation of the lien normal to the graph of f at x=1

how?

- Calc BC -
**Steve**, Friday, May 3, 2013 at 4:25pmthe line tangent to the graph at (x,y) has slope f'(x)

f'(x) = -4/(x+7)^2

f'(1) = -4/8^2 = -1/16

The line normal to f thus has slope +16

f(1) = 1/2

So, now we have a point (1,1/2) and a slope: 16

So, the line is

y - 1/2 = 16(x-1)

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