algebra
posted by strugglin .
Gail has a collection of nickels, dimes, and quarters that is worth $7.95 altogether. If she has three more nickels than dimes, and 38 coins altogether, then how many of each kind of coin does she have?

dimes  x
nickels  x+3
quarters  38x(x+3) = 352x
10x + 5(x+3) + 25(352x) = 795
10x + 5x + 15 + 875  50x = 795
35x = 80
no integer solution, so the question is flawed.
check my arithmetic, and check your typing