Post a New Question

algebra

posted by .

Gail has a collection of nickels, dimes, and quarters that is worth $7.95 altogether. If she has three more nickels than dimes, and 38 coins altogether, then how many of each kind of coin does she have?

  • algebra -

    dimes -- x
    nickels -- x+3
    quarters --- 38-x-(x+3) = 35-2x

    10x + 5(x+3) + 25(35-2x) = 795
    10x + 5x + 15 + 875 - 50x = 795
    -35x = -80
    no integer solution, so the question is flawed.

    check my arithmetic, and check your typing

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question