Thursday

December 18, 2014

December 18, 2014

Posted by **strugglin** on Thursday, May 2, 2013 at 11:31pm.

- algebra -
**Reiny**, Friday, May 3, 2013 at 7:12amdimes -- x

nickels -- x+3

quarters --- 38-x-(x+3) = 35-2x

10x + 5(x+3) + 25(35-2x) = 795

10x + 5x + 15 + 875 - 50x = 795

-35x = -80

no integer solution, so the question is flawed.

check my arithmetic, and check your typing

**Answer this Question**

**Related Questions**

math - Jo has 37 coins (all nickels, dimes and quarters) worth $5.50. She has 4 ...

algebra - Please help....struggling with word problems and please explain how to...

mathematics - In a collection of nickels, dimes and quarters, there are twice ...

mathematics - In a collection of nickels, dimes and quarters, there are twice ...

math - In a collection of nickels, dimes and quarters, there are twice as many ...

mathematics - In a collection of nickels, dimes and quarters, there are twice ...

Math - A collection of 30 coins worth $5.50 consists of nickels, dimes, and ...

Alegbra (Mrs.Sue) thank you :) - Sal keeps quarters,nickels, and dimes in a jar...

mathematics - In a collection of nickels, dimes and quarters, there are twice ...

algebra - A collection of nickels, dimes, and quarters amounts to $9.50. If ...