Posted by **strugglin** on Thursday, May 2, 2013 at 11:31pm.

Gail has a collection of nickels, dimes, and quarters that is worth $7.95 altogether. If she has three more nickels than dimes, and 38 coins altogether, then how many of each kind of coin does she have?

- algebra -
**Reiny**, Friday, May 3, 2013 at 7:12am
dimes -- x

nickels -- x+3

quarters --- 38-x-(x+3) = 35-2x

10x + 5(x+3) + 25(35-2x) = 795

10x + 5x + 15 + 875 - 50x = 795

-35x = -80

no integer solution, so the question is flawed.

check my arithmetic, and check your typing

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