posted by strugglin on .
Gail has a collection of nickels, dimes, and quarters that is worth $7.95 altogether. If she has three more nickels than dimes, and 38 coins altogether, then how many of each kind of coin does she have?
dimes -- x
nickels -- x+3
quarters --- 38-x-(x+3) = 35-2x
10x + 5(x+3) + 25(35-2x) = 795
10x + 5x + 15 + 875 - 50x = 795
-35x = -80
no integer solution, so the question is flawed.
check my arithmetic, and check your typing