Please help me answer this problem.How do I answer this if I don't have the mass of the monkey and the scooter together?
At a circus animal training facility, a monkey rides a miniature motorscooter at a speed of 7.0 m/s. The monkey and scooter together have a mass of m kg. Meanwhile, a chimpanzee on roller skates with a total mass of 44 kg moves at a speed of 1.5 meters per second. The magnitude of the momentum of the monkey plus scooter is how many times the magnitude of the momentum of the chimpanzee plus skates?
Thank you
To answer this problem, we need to compare the momentum of the monkey plus scooter to the momentum of the chimpanzee plus skates. Momentum is calculated as the mass of an object multiplied by its velocity.
The momentum of the monkey plus scooter can be expressed as P1 = (m kg) × (7.0 m/s). Similarly, the momentum of the chimpanzee plus skates is P2 = (44 kg) × (1.5 m/s).
Now, let's compare the magnitudes of these two momenta. The magnitude of a vector is its absolute value, so we don't have to worry about negative signs.
To find the ratio, we divide the magnitude of P1 by the magnitude of P2:
(P1 magnitude) / (P2 magnitude) = [(m kg) × (7.0 m/s)] / [(44 kg) × (1.5 m/s)]
To simplify, we can cancel out common units and divide:
(P1 magnitude) / (P2 magnitude) = (7.0 m/s) / (1.5 m/s) = 4.667
Therefore, the magnitude of the momentum of the monkey plus scooter is approximately 4.667 times the magnitude of the momentum of the chimpanzee plus skates.