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December 21, 2014

December 21, 2014

Posted by **John** on Thursday, May 2, 2013 at 9:35pm.

If Linda wants to be 90 percent Confident that her sample estimate of the proportion of voters who favor the bond is within 2 percent of the population percent p who favor the bond how large a sample should she use?

- statistics -
**dais**, Thursday, May 2, 2013 at 10:55pmn=(z*/m)squared(p*)(1-p*)

so be sure to square (z*/m)

m= margin of error, the invNorm for 90% is 1.645, p*=.5, if not given

The problem worked out:

(1.645/0.02)squared(.5)(1-.5)= 1691.265625 so the sample size should be 1691 people. Hope this helps

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