Small raindrops are actually perfectly spherical. The pressure difference between the inside and outside of a spherical raindrop of volume 4.2×10^−9 m^3 is 280 Pa. What is the surface tension in N/m of the water on the outside of the raindrop?
To determine the surface tension of the water on the outside of the raindrop, we can use the following formula:
Surface Tension = (Pressure Difference) / (2 × Radius)
First, let's calculate the radius of the raindrop using the given volume:
Volume of the raindrop = 4.2 × 10^(-9) m^3
We know that the volume of a sphere is given by the formula:
Volume of a sphere = (4/3) × π × (Radius)^3
Rearranging the formula, we can solve for the radius:
Radius = [(3 × Volume) / (4 × π)]^(1/3)
Now, calculate the radius:
Radius = [(3 × 4.2 × 10^(-9) m^3) / (4 × π)]^(1/3)
Next, substitute the value of the calculated radius into the formula for surface tension:
Surface Tension = (280 Pa) / (2 × Radius)
Calculate the surface tension:
Surface Tension = (280 Pa) / (2 × Radius)
The resulting value will be the surface tension in N/m of the water on the outside of the raindrop.