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July 30, 2014

July 30, 2014

Posted by **agora** on Thursday, May 2, 2013 at 5:50am.

- ahmadu university zaria nigeria -
**Steve**, Thursday, May 2, 2013 at 11:20amThe language is a bit unclear, but it appears that it takes 15 seconds to travel the 100 cm from A to B. If so,

since velocity

v = at

3at = a(t+15)

t = 15/2 s

Since distance

s = 1/2 at^2,

100 + 1/2 at^2 = 1/2 a(t+15)^2

a = 4/9 cm/s^2

So, we have

v@A = (4/9)(15/2) = 10/3

v@B = (4/9)(45/2) = 10

s@A = 1/2 (4/9)(15/2)^2 = 25/2

s@B = 1/2 (4/9)(45/2)^2 = 225/2

Note that 225/2 = 25/2 + 100 as required

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