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March 28, 2017

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A hoop of radius 0.50 m and a mass of 0.20 kg is released from rest and allowed to roll down an inclined plane. How fast is it moving after dropping a vertical distance of 3.0 m ?

  • physics - ,

    V^2 = Vo^2 + 2g*h
    V^2 = 0 + 19.6*3 = 58.8
    V = 7.67 m/s.

  • physics - ,

    It is 5.4 m/s

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