Wednesday

April 16, 2014

April 16, 2014

Posted by **KK** on Wednesday, May 1, 2013 at 10:20pm.

- Math -
**Reiny**, Wednesday, May 1, 2013 at 10:38pmI will assume that repeats are allowed as in most combination locks

so number of possible codes = 10^3 = 1000

So we want three 3's and one non-3

333x

33x3

3x33

x333---> where x is a number other than 3

so there are 4(9) of these or 36

so prob of our event = 36/1000 = 9/250

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