Tuesday

July 22, 2014

July 22, 2014

Posted by **Anonymous** on Wednesday, May 1, 2013 at 10:13pm.

please provide steps

- calc -
**Reiny**, Wednesday, May 1, 2013 at 10:25pm1/(1+(e^-x))

= 1/(1 + 1/e^x)

= 1/( (e^x + 1)/e^x )

= e^x/(e^x + 1)

now by "recognition" of how to differentiate Ln(anything) = anything'/anything

I get

∫1/(1+(e^-x)) dx

= ln(e^x + 1) + c

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