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What concentration of CH3NH3Br is necessary to prepare a pH = 10.00 buffer solution assuming the base concentration is 0.49 M (Kb for CH3NH2 = 4.4 x 10-4). In M

  • Chem - ,

    pH = pKa + log(base)/(acid)
    You have Kb, convert that to pKb, then to pKa by pKa + pKb = pKw = 14.

    (CH3NH3B) is the acid.
    pH = 10.0
    (base) = 0.49M
    Solve for (CH3NH3Br)

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