Methane gas is burned releasing Carbon Dioxide into the atmosphere. How much CO2 (g) is released if 78.5 Liters of Methane is burned? CH4 + O2 --> CO2 + H2O
CH4 + 2O2 ==> CO2 + 2H2O
When dealing with gases one may use a shortcut and not convert L to mols. Instead one may use L directly.
You have 78.4L CH4, convert that to L CO2 by
78.4 L CH4 x (1 mol CO2/1 mol CH4) = 78.4 x 1/1 = ?
To calculate the amount of carbon dioxide (CO2) released when burning a given amount of methane gas (CH4), you need to use stoichiometry and the balanced chemical equation. Here's how you do it step by step:
Step 1: Write the balanced chemical equation.
The balanced equation for the combustion of methane is:
CH4 + 2O2 --> CO2 + 2H2O
This equation tells us that one molecule of methane (CH4) reacts with two molecules of oxygen (O2) to produce one molecule of carbon dioxide (CO2) and two molecules of water (H2O).
Step 2: Convert liters of methane gas to moles.
To determine the number of moles of methane (CH4) present in 78.5 liters, you need to use the ideal gas law. However, for this calculation, we will assume standard temperature and pressure (STP), which is 0 degrees Celsius (273 K) and 1 atmosphere (1 atm) of pressure. At STP, 1 mole of any gas occupies 22.4 liters.
So, the number of moles of methane (CH4) = Volume (liters) / 22.4
Number of moles of CH4 = 78.5 / 22.4
Step 3: Use stoichiometry to find moles of CO2 produced.
From the balanced chemical equation, we can see that the stoichiometric ratio between methane and carbon dioxide is 1:1. This means that for every mole of methane burned, one mole of carbon dioxide is produced.
Therefore, the number of moles of carbon dioxide (CO2) = number of moles of CH4 from Step 2.
Step 4: Convert moles of CO2 to grams.
The molar mass of carbon dioxide (CO2) is approximately 44 grams per mole. To find the mass of CO2 produced, you multiply the number of moles of CO2 by its molar mass.
Mass of CO2 = number of moles of CO2 * molar mass of CO2
Step 5: Calculate the final answer.
Plugging in the values obtained from the previous steps, you can now calculate the mass of carbon dioxide (CO2) released when 78.5 liters of methane is burned.
Mass of CO2 = (number of moles of CH4) * (molar mass of CO2)
= (78.5 / 22.4) * 44
= 156.86 grams
Therefore, approximately 156.86 grams of carbon dioxide (CO2) would be released if 78.5 liters of methane gas were burned.