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October 31, 2014

October 31, 2014

Posted by **Karry** on Wednesday, May 1, 2013 at 9:07pm.

Parabola equation y= 4(100 - x^2/2500)

x and y are measured in feet

A. Find the length of the road across the bridge

B. find the height of the parabolic arch at the center of the span

C. Find the lengths of the vertical girders at intervals of 100 feet from the center of the bridge

( graph of upside down parabola)

problem is on photobucket

username: piggerockalbum

album: math problems

- college algebra -
**Reiny**, Wednesday, May 1, 2013 at 9:26pmI can't log into your photobucket, (needs password)

so I will "guess" at a diagram

expanding and simplifying your equation I got

y = (-1/625)x^ + 400

b) at the centre, x = 0

so y = 400

the bridge is 400 ft high

width of bridge, let y = 0 (on the x-axis)

0 = (-1/625)x^2 + 400

x^2 = (625)(400)

x = ±25(20) = ±500

So the bridge is 1000 ft wide

for vertical girders

let x = 100, 200, 300 , 400

x = 100

y = (-1/625)(100)^2 + 400 = 384

x = 200

y = (-1/625)(200)^2 + 400 = 336

etc.

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