Tuesday

March 31, 2015

March 31, 2015

Posted by **Anonymous** on Wednesday, May 1, 2013 at 8:01pm.

- Pre-Cal -
**Reiny**, Wednesday, May 1, 2013 at 8:20pmtotally unclear

is there an argument after tan-1 ??

did you mean tan^-1 or something like that?

is the right side = 43/9.3 ?

I will assume you meant:

tan^-1 = 43/9.3

= 4.6236...

= 77.796

**Answer this Question**

**Related Questions**

Pre Cal. - Evaluate tan(cos^(-1)(3/2 )+tan^(-1)(3/3))? arccos(sqrt(3) / 2...

Pre-Cal - Perform the addition or subtraction and use the fundamental identities...

Pre-Cal - 1)tan 5 degrees + tan 25 degrees / 1 tan 5 degrees tan 25 degrees = ...

Pre-cal/Trig - (tan/(1+sec)) + ((1+sec)/tan) = 2csc (Show all work please.)

Pre Cal - tan 2x- tan 6y/ 1+ tan 2x tan 6y

Pre Cal - cos^2+tan^2=1

pre-cal - tan((theta/2)+(pi/6))=-1

Pre-Cal - Perform the addition or subtraction. tanx - sec^2x/tanx tan^2(x)/tan(x...

Pre Cal - the function y= tan (x/3) has an x intercept at?

pre cal - verify each identity tan(x/2)=tanx/secx+1