Posted by **Tim** on Wednesday, May 1, 2013 at 3:03pm.

A 17 foot ladder is placed against a wall. if the foot of the ladder is pushed toward the wall at 0.5 feet per second, how fast is the top of the ladder rising when the foot is 8 feet from the wall?

- Elements of Calc. -
**Steve**, Wednesday, May 1, 2013 at 3:15pm
at the moment in question, the height is 15. If the base of the ladder is x from the wall, and the height is y,

x^2+y^2 = 17^2

2x dx/dt + 2y dy/dt = 0

2(8)(-.5) + 2(15) dy/dt = 0

dy/dt = 4/15

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