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November 26, 2014

November 26, 2014

Posted by **Lynn** on Tuesday, April 30, 2013 at 11:21pm.

pH = - log [H+]

What is the pH of a solution whose [H+] is 0.0007 M?

i got it as 7.0 i know it is wrong

2. What is the [H+] in a solution having a pOH of 6 ?

isn't it supposed to add to 14? so 8? but it didn't work

- Chemistry -
**DrBob222**, Tuesday, April 30, 2013 at 11:42pma.

pH = -log(H^+)

pH = -log(7E-4)

pH = -(-3.15)

pH = 3.15

b.

pH + pOH = pKw = 14

pH + 6 = 14

pH = 8

The problems asks for (H^+); therefore,

pH = -log(H^+)

8 = -log(H^+)

-8 = log(H^+)

(H^+) = 1E-8

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