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September 20, 2014

September 20, 2014

Posted by **ianian** on Tuesday, April 30, 2013 at 8:40pm.

x

x^log5 =x^3/25.

- MAths -
**Reiny**, Tuesday, April 30, 2013 at 9:28pmWhat does that lone x just hanging around there ?

if you mean

x^log5 = x^(3/25)

then log 5 = 3/25 , which makes no sense

- MAths -
**ianian**, Tuesday, April 30, 2013 at 10:37pmWhat is the sum of all possible real values of x that satisfies the equation xlog5x=x325.

- MAths -
**Reiny**, Wednesday, May 1, 2013 at 7:26amStill not clear enough

is it

xlog(5x) or xlog_{5}x ?

on the right side, originally you had x^(3/25

now I see

x325

is it x^325 or x^(3/25) like before ????

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