Posted by **Marshall** on Tuesday, April 30, 2013 at 8:05pm.

Two rulers are the same length. Ruler A is divided into 357 units while ruler B is divided into 255 units The rulers are placed side by side with the 0 marks lined up and the 375th mark of ruler A aligned with the 255th mark of ruler B. How many total places will the marks on the rulers be aligned?

- math -
**Reiny**, Tuesday, April 30, 2013 at 9:51pm
357A = 255B

A/B = 255/357 = 5/7

A - B

5 7

10 14

15 21

...

255 357

**there will be 52 of those line-ups** , obtained by 255/5 = 51, or 357/6 = 51, plus the line-up at the zeros

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