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January 27, 2015

January 27, 2015

Posted by **Marshall** on Tuesday, April 30, 2013 at 8:05pm.

- math -
**Reiny**, Tuesday, April 30, 2013 at 9:51pm357A = 255B

A/B = 255/357 = 5/7

A - B

5 7

10 14

15 21

...

255 357

**there will be 52 of those line-ups**, obtained by 255/5 = 51, or 357/6 = 51, plus the line-up at the zeros

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