Wednesday

August 27, 2014

August 27, 2014

Posted by **Leila** on Tuesday, April 30, 2013 at 6:58pm.

Lmin= 0 kg*m^2/s

What is the largest possible value for the angular momentum L of an electron in the n=5 shell?

What is the Lmax? Please help I don't get this.Thank you!

- Physics -
**Elena**, Wednesday, May 1, 2013 at 3:20amL=ℏ √l(l+1) =√l(l+1)• h/2π

l= n-1 =>

l=0, 1, 2, 3,4.

L(max) = √(4•5) • 6.63•10⁻³⁴/2π=4.72•10⁻³⁴ kg•m²/s

L(min)= 0

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