Chromium(III) chloride(aq) + potassium sulfide(aq)
what are the products of this reaction
The products of the reaction between chromium(III) chloride (CrCl3) and potassium sulfide (K2S) are chromium(III) sulfide (Cr2S3) and potassium chloride (KCl).
To determine the products of a chemical reaction, we need to consider the chemical formulas of the reactants and their respective charges.
The reactants in this reaction are:
Chromium(III) chloride (CrCl3(aq))
Potassium sulfide (K2S(aq))
First, let's break down the compounds into their respective ions:
Chromium (III) chloride:
Cr3+ (cation) + 3 Cl- (anions)
Potassium sulfide:
2 K+ (cations) + S2- (anion)
Now, we need to combine the ions to form the products. The general rule is that positive ions (cations) combine with negative ions (anions).
In this case, the positive ion Cr3+ combines with the negative ion S2- to form one of the products:
Cr3+ + S2- → Cr2S3
Next, we need to look at the remaining ions:
3 Cl- + 2 K+ → 2 KCl
So, the products of this reaction are:
Cr2S3 (Chromium sulfide)
2 KCl (Potassium chloride)
Thus, Chromium(III) chloride reacts with potassium sulfide to produce chromium sulfide (Cr2S3) and potassium chloride (KCl).
Naturally, just switch the ions:
chromium sulfide and potassium chloride