I NEED HELP WITH,
Of the 52 plays attributed to a play
wright,15 are comedies,18 are tragedies,and 19 are histories. if one play is selected at random, find the odds against selecting a comedy.
prob(comedy) = 15/52
prob(not a comedy) = 1 - 15/52 = 37/52
odds against comedy = (37/52) : (15/52)
= 37 : 15
To find the odds against selecting a comedy, we need to determine the number of unfavorable outcomes (plays that are not comedies) to the number of favorable outcomes (comedies).
Given that there are 52 total plays, and out of these, 15 are comedies, then the number of plays that are not comedies would be:
Total plays - Comedies = 52 - 15 = 37
Therefore, there are 37 plays that are not comedies.
Now, to calculate the odds against selecting a comedy, we divide the number of unfavorable outcomes by the number of favorable outcomes:
Odds against = Number of unfavorable outcomes / Number of favorable outcomes
Odds against = 37 / 15
Simplifying this ratio, we get:
Odds against = 37:15
So, the odds against selecting a comedy are 37 to 15.