Posted by **MAths lover Please Helppppp** on Tuesday, April 30, 2013 at 5:56am.

We are given that log102<0.302. How many digits are there in the decimal representation of 5^500?

- Maths -
**Reiny**, Tuesday, April 30, 2013 at 8:39am
I am sure you meant:

log_{10} 2 < .302

(you could have just said log 2 ≤ .302 , if the base is omitted it is assumed to be base 10)

let x = 5^500

= (10/2)^500

log x = log (10/2)^500

log x = 500(log (10/2)

= 500(log10 - log2)

= 500(1 - log2)

= 500 - 500log2

= 500 - 151 , = 349 from your given

= 349.48 by using calculator for log2

so your log x > 349

what does that mean?

if logx = 2 , then x = 10^2 ---100 --- 3 digits

if logx = 3, then x = 10^3 -- 1000 --- 4 digits

...

if logx = 349 , then x = 10^349 ----- 350 digits

but log x > 349 , so it must contain 351 digits

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