Posted by mag on .
I need help with the linear equation:
10  0.5y = 1.5x and y = 0.5(6x + 40)

algebra 
Henry,
10  0.5y = 1.5x
1.5x  0.5y = 10
Multiply both sides by 2:
Eq1: 3x + y = 20
y = 0.5(6x+40)
y = 3x + 20
Eq2: 3x + y = 20
Add Eq1 and Eq2:
2y = 40
Y = 20
In Eq1. replace y with 20:
3x + 20 = 20
3x = 2020 = 0
X = 0.
Solution Set: (x,Y) = (0,20).