Posted by **tsong** on Monday, April 29, 2013 at 11:26am.

a, b, c, d and e are distinct integers such that (5−a)(5−b)(5−c)(5−d)(5−e)=28. What is the value of a+b+c+d+e?

- number theory and algebra -
**Steve**, Monday, April 29, 2013 at 11:33am
well, since the only factors of 28 are ±1,±2,±4,±7 I'd have to go with

(2)(-2)(1)(-1)(7)

(5-3)(5-7)(5-4)(5-6)(5-(-2)) = 28

3+7+4+6-2 = 18

- number theory and algebra -
**tsong**, Monday, April 29, 2013 at 11:47am
thanks...

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