Posted by tsong on Monday, April 29, 2013 at 11:26am.
a, b, c, d and e are distinct integers such that (5−a)(5−b)(5−c)(5−d)(5−e)=28. What is the value of a+b+c+d+e?

number theory and algebra  Steve, Monday, April 29, 2013 at 11:33am
well, since the only factors of 28 are ±1,±2,±4,±7 I'd have to go with
(2)(2)(1)(1)(7)
(53)(57)(54)(56)(5(2)) = 28
3+7+4+62 = 18

number theory and algebra  tsong, Monday, April 29, 2013 at 11:47am
thanks...
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