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posted by Chris on Monday, April 29, 2013 at 11:17am.
For z1 = 4cis(7pi/6)and z2 = 3ci(pi/3), find z1 · z2 in rectangular form. A.12 − 12i B.-12 − 12i C.12 + 12i D.12i E.-12i
just multiply moduli and add arguments: (4)(3)cis(7pi/6 + pi/3) 12 cis 3pi/2 (E)
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