Posted by Chris on .
For z1 = 4cis(7pi/6)and z2 = 3ci(pi/3), find z1 · z2 in rectangular form.
A.12 − 12i
B.12 − 12i
C.12 + 12i
D.12i
E.12i

Calc 
Steve,
just multiply moduli and add arguments:
(4)(3)cis(7pi/6 + pi/3)
12 cis 3pi/2
(E)