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March 3, 2015

March 3, 2015

Posted by **ianian** on Monday, April 29, 2013 at 4:13am.

- Maths -
**Reiny**, Monday, April 29, 2013 at 8:26amso we are looking for

1 + x^2 + x^4 being a prime

x^4 + x^2 + 1

= x^4 + 2x^2 + 1 - x^2

= (x^2 + 1)^ - x^2 ---- a difference of squares

= (x^2 + 1 +x)(x^2 + 1 -x)

if x = 1 , we get

(1+1+1)(1) = 3 --- a prime number

for any other value of x, the value of each bracket > 1

and 1+x^2 + x^4 is the product of at least two factors

thus : 1 + 1^2 + 1^4 is the only such case

1 1 1 is the only case

- Maths -
**tsong**, Monday, April 29, 2013 at 11:13am111 is incorrect

- Maths -
**PD**, Tuesday, April 30, 2013 at 2:57pm@Tsong, the answer is not 111, the answer is 3 :P

- Maths -
**PD**, Tuesday, April 30, 2013 at 2:58pmsorry, the answer is 1 :P

- Maths -
**abc**, Saturday, May 4, 2013 at 2:57amthanxxxx

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