posted by rex on .
How many grams of water, H(subscript 2)O, and propene, C(subscript 3)H(subscript 6), can be formed from the reaction of 6.0 g of 2-propanol, C(subscript 3)H(subscript 8)O?
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C3H8O ==> C3H6 + H2O
mols C3H8O = grams/molar mass
Convert mols C3H8O to mols H2O using the coefficients in the balanced equation. (The ratio is 1:1).
Now convert mols H2O to grams.
g = mols H2O x molar mass H2O