1.)A ballon is filled with 3.0L of helium at 310k.The balloon is placed in an oven where the temputure reaches 340k.what is the new volume of the ballon?
~3.29L = V2~
++++Explanation++++
Formula: V1/T1 = V2/T2
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Given:
V1 = 3.0 L V2 = ?
T1 = 310 K T2 = 340 K
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Plugin:
(X stands in place of V2 just to make it easier to look at)
[3.0L / 310K = X / 340K]
(3.0L / 310K = 0.01L/K)
0.01L/K = X / 340K
(multiply 340K on both sides, it cancels out on the right)
0.01L/K * 340K = X
(0.01L/K * 340K = 3.29L)
**3.29L = X**
[or]
**3.29L = V2**
To find the new volume of the balloon, we can use the combined gas law equation, which relates the initial and final conditions of temperature and volume. The formula is:
(P₁ * V₁) / T₁ = (P₂ * V₂) / T₂
Where:
P₁ is the initial pressure (which is assumed to be constant)
V₁ is the initial volume
T₁ is the initial temperature
P₂ is the final pressure (which is assumed to be constant)
V₂ is the final volume (what we want to find)
T₂ is the final temperature
In this case:
V₁ = 3.0 L (initial volume of the balloon)
T₁ = 310 K (initial temperature)
T₂ = 340 K (final temperature)
Assuming the pressure remains constant, we can rearrange the equation to solve for V₂:
V₂ = (P₁ * V₁ * T₂) / (T₁ * P₂)
Since the pressure is not given in the question, we can assume that it remains constant. Therefore, we can simplify the equation to:
V₂ = (V₁ * T₂) / T₁
Substituting the given values:
V₂ = (3.0 L * 340 K) / 310 K
Calculating the right side of the equation:
V₂ = 3.27 L
Therefore, the new volume of the balloon is approximately 3.27 liters when the temperature reaches 340 K in the oven.