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December 21, 2014

December 21, 2014

Posted by **Anonymous** on Sunday, April 28, 2013 at 12:35pm.

- Math -
**Reiny**, Sunday, April 28, 2013 at 12:45pm40 = 1(2)^(6/k) , where k is the doubling time in hours

log 40 = log (2^(6/k) )

log 40 = (6/k) log 2

6/k = log 40/ log 2

k = 6log2/log40 or log 64/log40

since you asked for the "exact" doubling time, that is your answer

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