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December 18, 2014

December 18, 2014

Posted by **borat** on Sunday, April 28, 2013 at 9:27am.

Your task is to determine exactly how many minutes could be saved if all 3 painters work together on the fence, as compared to only Peter and Paul doing the job in tandem.

Determine how many additional minutes would be saved (beyond those found above) if Mary were able to paint the fence alone in 6 hours instead of 8 hours?

- math -
**Reiny**, Sunday, April 28, 2013 at 12:24pmpeter's rate = f/6

pat's rate = f/3

mary's rate = f/8

combided rate of all 3 = f/6 + f/3 + f/8

= 5f/8

time using all 3 = f/(5f/8) = 8/5 hrs or 1.6 hrs or

1 hour and 36 minutes

using only peter and paul = f/6 + f/3 = f/2

so time for the two of them is f/(f/2) = 2 hrs

so using Mary would save them 2 hrs - 8/5 hrs or 24 minutes

You should have no difficulty repeating the calculations for the last part of the question.

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