a sample of molybdenum is analysed by x-ray diffraction using Nik(alpha) radiation.

calculate value of angle of which the lowest angle of radiation is observed .
answer in degrees.

To calculate the value of the angle at which the lowest angle of radiation is observed in the x-ray diffraction of molybdenum, you'll need to use Bragg's Law. Bragg's Law relates the angle of diffraction (θ), the wavelength of the X-ray radiation (λ), and the distance between atomic planes (d) within the crystal lattice.

Bragg's Law is given by:

nλ = 2d sin(θ)

Where:
- n is the order of diffraction (usually equal to 1 for the first-order diffraction)
- λ is the wavelength of the X-ray radiation
- d is the distance between adjacent atomic planes in the crystal lattice
- θ is the angle of diffraction

For molybdenum, the value of d is 0.2204 nm.

Now, let's calculate the angle θ.

First, we need to find the wavelength (λ) of the X-ray radiation. The symbol "Nik(alpha)" might refer to a specific wavelength used for diffraction, but to perform the calculation, we'll need the value in angstroms (Å).

If you have the value for Nik(alpha) radiation in angstroms, you can divide it by 10 to convert it to nanometers. Then you can proceed with the calculation.

For example, let's assume the wavelength of Nik(alpha) radiation is 1.54 Å. Dividing it by 10, we get λ = 0.154 nm.

Now, we can rearrange Bragg's Law and solve for θ:

θ = arcsin(nλ / (2d))

Plugging in the values:

θ = arcsin((1 * 0.154 nm) / (2 * 0.2204 nm))

Calculating this with a scientific calculator, the value of θ is approximately 20.7 degrees.

Therefore, the lowest angle of radiation observed in the x-ray diffraction of molybdenum using Nik(alpha) radiation is approximately 20.7 degrees.