calculate density of atoms in(001) in Lithium

answer in units of atoms/cm2

1.15*10^15

1.15e15

To calculate the density of atoms on the (001) plane in Lithium, you need to know the lattice constant (a) and the atomic weight (M) of Lithium.

The lattice constant is the distance between adjacent atoms in a crystal structure. For Lithium, the lattice constant is typically around 3.49 Angstroms (Å).

The atomic weight of Lithium is 6.94 g/mol.

1. First, convert the lattice constant from Angstroms to centimeters:
1 Å = 1 x 10^-8 cm. Therefore, 3.49 Å = 3.49 x 10^-8 cm.

2. Next, calculate the area of the (001) plane:
The (001) plane is a square, so its area can be calculated by squaring the lattice constant:
Area = (3.49 x 10^-8 cm) x (3.49 x 10^-8 cm) = 1.21601 x 10^-15 cm^2.

3. Determine the number of atoms in the area of the (001) plane:
The (001) plane contains one atom per unit cell. For a simple cubic crystal like Lithium, there is only one atom in each unit cell.

4. Calculate the density of atoms on the (001) plane in units of atoms/cm^2:
Density = Number of atoms / Area
= 1 atom / (1.21601 x 10^-15 cm^2)
≈ 8.22 x 10^14 atoms/cm^2

Therefore, the density of atoms on the (001) plane in Lithium is approximately 8.22 x 10^14 atoms/cm^2.