Post a New Question


posted by .

The boom weighs 2450 and is attached to a friction less pivot at its lower end. It is not uniform; the distance of its center of gravity from the pivot is 39.0 of its length.

What is the tension in the guy wire?

Link to picture of problem which is needed to solve the problem , copy paste the link in address bar, then type in com after tinypic. , then press enter in address bar: tinypic./view.php?pic=53qp3m&s=5

Thanks in advance

  • Physics -

    assume boom weighs 2450 Newtons
    HAVE to Know Length of boom (I will call it L)

    clockwise moments about base of boom
    5000 L cos 60 + 2450 (39) cos 60

    counterclockwise moments
    T L sin 60
    T = (5000 L + 2450(39) )cos 60/(L sin 60)

Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions

Post a New Question