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October 1, 2014

October 1, 2014

Posted by **Michaela** on Saturday, April 27, 2013 at 8:24pm.

A) What are the dimensions of such a cylinder which has maximum volume?

B) What is the radius?

C) What is the height?

- Calculus -
**Reiny**, Sunday, April 28, 2013 at 5:31amMake a cross-section diagram showing a rectangle within a triangle, or if you are artistically inclined, make a drawing of the cylinder within the cone.

Let the radius of the cylinder be r,

let its height be h

by similar triangles,

h/(2-r) = 5.5/2

2h = 11 - 5.5r

h = (11-5.5r)/2

volume of cylinder

= πr^2 h

= πr^2 (11 - 5.5r)/2

= (11/2)πr^2 - (5.5/2π r^3

d(volume)/dr = 11πr - (16.5/2)π r^2

= 0 for a max of volume

11πr - 8.25πr^2 = 0

divide out the π and factor out an r

r(11 - 8.25r) = 0

r = 0 or r = 11/8.25

clearly r = 0 would give a "minimum" so

r = 11/8.25 or 4/3

the h = (11 - 5.5(4/3) )/2 = 11/6

A) to obtain a maximum volume,

the radius is 4/3 and the height is 11/6

B) and C) answered in A)

check my arithmetic

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