How much mL of 0.2 M NaOH are needed to titrate vinegar while doing a titration with Phenolphthalein?

Sorry It should be 10.00 ml of vinegar!!!

What is the strength of vinegar you are using?

It is just vinegar that we did in the class. We used about 55 ml of vinegar to titrate.

I can show you how to solve the problem but I have no numbers. However,

mL vin x M vin = mL NaOH x M NaOH
If you substitute mL vinegar and multiply by M vinegar (molarity = mols/L) and divide by M NaOH you can calculate mL NaOH. Most vinegars are about 5% acetic acid and I believe that is % w/v which makes it about 0.833 M.

To determine the amount of NaOH needed to titrate the vinegar, you need some additional information. Specifically, you need to know the volume of vinegar that you plan to titrate and the concentration of acetic acid in the vinegar.

Once you have this information, you can follow these steps to calculate the required amount of NaOH:

1. Write the balanced chemical equation for the reaction between NaOH and acetic acid in vinegar:
CH3COOH + NaOH → CH3COONa + H2O

2. Find the molar ratio between NaOH and acetic acid in the equation. From the equation, you can see that one mole of acetic acid reacts with one mole of NaOH.

3. Calculate the number of moles of acetic acid in the vinegar:
Moles of acetic acid = volume of vinegar (in L) × concentration of acetic acid (in mol/L)

4. Since the molar ratio between NaOH and acetic acid is 1:1, the number of moles of NaOH required is equal to the moles of acetic acid.

5. Finally, calculate the volume of 0.2 M NaOH needed using the equation:
Volume of NaOH (in L) = Moles of NaOH / Concentration of NaOH (in mol/L)

Follow these steps with the volume of vinegar and concentration of acetic acid you have to determine the volume of 0.2 M NaOH needed for the titration.