Sunday
April 20, 2014

Homework Help: calculus

Posted by Brandy on Friday, April 26, 2013 at 3:49pm.

The height of a projectile launched into the air is given by h (t)= -16t^2 + 48t + 60, where h is the height of the projectile in feet above the ground and t is the number of seconds after its launch. Find the *instantaneous rate of change* in the height of the projectile at 1.5 seconds. It is supposed to be 24 feet per second. Isn't it just -32t + 48 and then putting the 1.5 in for that t?

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

Physics - A projectile is fired up into the air at a speed of 164 m/s at an ...
Physics - A projectile is launched with an initial speed of 40m/s at an angle of...
intermediate algebra - A projectile is launched directly upward from the top of ...
physics - a projectile with mass (m)=35grams is placed on a vertically ...
physics - a projectile with mass (m)=35grams is placed on a vertically ...
Math/calculus - a toy rocket is shot into the air at the top of a building so ...
physics - three more questions: 1) A 1.50kg projectile is launched at 18.0m/s ...
physics - A 3Kg projectile is fired straight upward from earth's surface with a ...
physics - A projectile with mass of 139 kg is launched straight up from the ...
math - A projectile is launched vertically upward from the top of a 240-foot ...

Search
Members