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A spherical shell of radius R carries a uniform surface charge density (charge per unit area) σ. The center of the sphere is at the origin and the shell rotates with angular velocity ω (in rad/sec) around the z-axis (z=0 at the origin). Seen from below, the sphere rotates clockwise. (See the figure below)


(a) Calculate the magnitude of the total current (in A) carried by the rotating sphere for the following values of σ, ω and R:
σ= 6 ×10−4C m−2, ω= 7 rad⋅s−1 and R=1m


unanswered
(b) Calculate the magnitude of the magnetic field B(z) (in T) that is generated by the circular current of the rotating shell at a point P on the z-axis for the following values of σ, ω , z and R:
σ= 6 ×10−4C m−2, ω= 7 rad⋅s−1, z= 1.6 m and R=1m


unanswered

  • Physics - ,

    a) 0
    b) 0

  • Physics - ,

    a) I = 52.78 e-3

    b) B = 5.53 e-8 T

  • Physics - ,

    Anonymous, can you provide formula because of different values please?

  • Physics - ,

    a) Calculate the magnitude of the total current (in A) carried by the rotating sphere for the following values of ƒÐ, ƒÖ and R:
    ƒÐ= 6 ~10−4C m−2, ƒÖ= 7 rad⋅s−1 and R=1m


    (b) Calculate the magnitude of the magnetic field B(z) (in T) that is generated by the circular current of the rotating shell at a point P on the z-axis for the following values of ƒÐ, ƒÖ , z and R:
    ƒÐ= 6 ~10−4C m−2, ƒÖ= 5 rad⋅s−1, z= 1.92 m and R=1m

  • Physics - ,

    (a) Calculate the magnitude of the total current (in A) carried by the rotating sphere for the following values of ó, ù and R:
    sigma= 6x10−4C m−2, w= 5 rad⋅s−1 and R=1m

    b) Calculate the magnitude of the magnetic field B(z) (in T) that is generated by the circular current of the rotating shell at a point P on the z-axis for the following values of ó, ù , z and R:
    sigma= 6x10−4C m−2, w= 7 rad⋅s−1, z= 1.6 m and R=1m

  • Physics - ,

    b) Calculate the magnitude of the magnetic field B(z) (in T) that is generated by the circular current of the rotating shell at a point P on the z-axis for the following values of ó, ù , z and R:
    sigma= 6x10−4C m−2, w= 5 rad⋅s−1, z= 1.6 m and R=1m

  • Physics - ,

    b) Calculate the magnitude of the magnetic field B(z) (in T) that is generated by the circular current of the rotating shell at a point P on the z-axis for the following values of ó, ù , z and R:
    sigma= 6x10−4C m−2, w= 5 rad⋅s−1, z= 1.92 m and R=1m

  • Physics - ,

    a) (a) Calculate the magnitude of the total current (in A) carried by the rotating sphere for the following values of sigma,omega and R:
    sigma = 5 times 10^{-4},C/m^2, omega = 4 rad/sec and R = 1 m

    b)(b) Calculate the magnitude of the magnetic field B(z) (in T) that is generated by the circular current of the rotating shell at a point P on the z-axis for the following values of sigma, omega , z and R:
    sigma = 5 times 10^{-4} {C m}^{-2}, \omega = 4 rad/sec , z= 2.1 m and R =1m

  • Physics - ,

    a) I = Sigma*A*omega
    b) B = mu*I/(2*(z-R))

  • Physics - ,

    How to calculate 'A'???

  • Physics - ,

    @Phy
    with spherical surface

  • Physics - ,

    That is a wrong formula, i m getting my answers wrong

  • Physics - ,

    Have the same problem, how to calculate for A?

  • Physics - ,

    Me too please help!

    (a) Calculate the magnitude of the total current (in A) carried by the rotating sphere for the following values of ó, ù and R:
    sigma= 6x10−4C m−2, w= 5 rad⋅s−1 and R=1m

    b) Calculate the magnitude of the magnetic field B(z) (in T) that is generated by the circular current of the rotating shell at a point P on the z-axis for the following values of ó, ù , z and R:
    sigma= 6x10−4C m−2, w= 5 rad⋅s−1, z= 1.92 m and R=1m

  • Physics - ,

    A=4*pi*r*r

  • Physics - ,

    Thanks Phy:
    is this right?
    a) I = Sigma*A*omega
    6*10^-4*4*pi*1*1*5
    I don't seem to get it right.

    b) mu*I/(2*(z-R))
    (6*10^-4)/(2*(1.92-1))
    I am not sure, if I found I though. Please could someone help?
    thanks

  • Physics - ,

    Yeah even i got it wrong, the formula itself is wrong

  • Physics - ,

    Oh, I see.
    Anonymous or someone else, could you maybe provide an example with real numbers? That would also help others.

  • Physics - ,

    Yes, please if possible provide answer with one example,thankyou!

  • Physics - ,

    Rubens can show example with real number please?

  • Physics - ,

    Phy, did you by any chance manage Problems?

    Bainbridge mass spectrometer

    Magnetic Field of a current-carrying ribbon

    Second RL Circuit

    Magnetic Field of a loop: I got Bx and By but Bz could not figure out Bz.

    I have Problems 1 (RL Circuit) and 2.

  • Physics - ,

    Pls Flu post 1 and 2.

  • Physics - ,

    Problem 1 as follows:
    a)
    I1:(R1+R2)/V
    I2:(R1+R2)/V
    I3:0

    b)
    I1:V/R1
    I2:0
    I3:V/R1

    Problem 2:
    I got right like this:
    if V right reads -0.5
    then multiply by two and drop the minus, so a) 1
    b) is the same value without minus, so b) 0.5

    Anyone for the other problems please?

  • Physics - ,

    Thanks FLu, I got it now.
    Please someone for the other problems?

  • Physics - ,

    Me too thanks FLu!

    Please explanation for other problems?

  • Physics - ,

    Anyone?

  • Physics - ,

    Has anybody got the explanation for other problems please?

  • Physics - ,

    Anybody!

  • Physics - ,

    a) I = Sigma*A*f
    f = omega/(2pi)

    b) B = mu*I/(2*(z-R))

  • Physics - ,

    Value of mu? Please

  • Physics - ,

    The other problems?

    Bainbridge mss spectrometer

    Magnetic Field of a current-carrying ribbon

    Second Rl circuit

    magnetic Field of a loop - Bz.

  • Physics - ,

    Is value for mu not 1.25663706*10^-6? Is it different to mu_0 then?

    can you show us an example with the above numbers please?

  • Physics - ,

    Anonymous can you tell me what the value for A is then?

    Something does not add up.
    This calculation below looks odd to me:
    (6*10^-4*4*pi*1*1*5)*(omega/2*pi)
    Anyone did figure out yet?

  • Physics - ,

    Anonymous, the formula is wrong. Did you get the answer right by the way?

    If somebody got the answer could they provide it step by step with numbers though?

    thanks

  • Physics - ,

    I got the a) right, the formula is:

    I = Sigma*A*f
    f = omega/(2pi)

    i got the b) wrong, i guess Mu is not 4piE-7

  • Physics - ,

    oh I see, so there is a difference between mu and mu_0. I cannot find any values as well.

    could you just help me with calculation a) please?
    If my values are:
    sigma= 6x10−4C m−2, w= 5 rad⋅s−1 and R=1m
    Is A= 4*pi*r*r ? if not could you correct my values below Anonymous please?

    Formula for a)
    (6x10-4*4*pi*1*1)*(5/2*pi)

    I think I am making mistakes with value A, please correct me Anonymous. Thanks!

  • Physics - ,

    You should be using mu/4pi for answer in b

  • Physics - ,

    you mean this is the formula for b) Anon?(mu/4*pi)/(2*(z-R))
    Is mu same as mu_0?
    thanks
    could you also check if my procedure for a) is right Anon?
    thanks

  • Physics - ,

    yes it is good

  • Physics - ,

    This procedure is right Anon really?
    I have just one try left can somebody check please?
    a)(6x10-4*4*pi*1*1)*(5/2*pi)

    b)(mu/4*pi)/(2*(z-R))

  • Physics - ,

    you are missing the current I in b

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    I is the result from problem a) right?

    Could you give me the complete formula or correct the above please Anon?

  • Physics - ,

    anyone for part b please,clearly

  • Physics - ,

    correct

  • Physics - ,

    before I forget mu is the value this:
    1.25663706*10^-6 ?

  • Physics - ,

    yes but you need mu/4pi

  • Physics - ,

    Anon, is it this formula for b) then please?

    b)(mu*I/4*pi)/(2*(z-R))
    and as Naseng said is the value for mu=
    1.25663706*10^-6
    if not what is it?

  • Physics - ,

    mu ia mu_0

  • Physics - ,

    Anon, many thanks now a) I got but stuck with b)
    I would be forever greatful, if I can figure b) out with your help.
    a) 0.007 so that is my I

    b)(mu*I/4*pi)/(2*(z-R))
    (1.25663706*10^-6*0.007/4*pi)/(2*(2.2-1)

    I followed your advice, but there seems to be an error in my calculation, could you help please? That would also help others to figure out. I am wondering if it is a bracket missing or if one of the values are wrong.

    Thanks for time Anon!

  • Physics - ,

    mu = 4pi * 10^(-7)

  • Physics - ,

    i used this getting wrong answer

  • Physics - ,

    Thanks Anon but 1.25663706*10^-6 is 4*pi*10^-7, please check if you like.

    It still does not work, any other suggestion, am I missing a bracket somewhere?

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    did u get it right FLU?

  • Physics - ,

    hmmmm do not use for b) yet as there seems to be missing but I got a) right so can assure you the formula must be right.

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    No, but I think we are near there is something missing but cannot figure it out, maybe a bracket issue!? Anon any suggestion or even Anonymous? You are usually great help guys! thanks

  • Physics - ,

    Anon could you write the formula for b) please with the above numbers? would be very helpful.

  • Physics - ,

    (I*10^(-7))/(2*(z-R))

  • Physics - ,

    Anon thanks, I thought it is
    (I*4*pi*10^(-7))/(2*(z-R))
    did you not say mu is=
    4pi * 10^(-7) ?

  • Physics - ,

    @anon this formula works for my friend but not for me I don't know what is the problem going on perhaps the formula isn't derived correctly...:(

  • Physics - ,

    yes i did and i also said you need to use
    mu/4pi

  • Physics - ,

    @FLu let me know if u got the correct answer with this formula and what it is ?

  • Physics - ,

    you need to make sure you use the right value for I

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    anyone has answer for other problems

  • Physics - ,

    Yup I've got I correct it is: 8.4*10^-3
    sigma= 7 ×10−4C m−2, ω= 6 rad⋅s−1, z= 1.9 m and R=1m

    and B as i calculated: 4.66*10^-10 but the grader is not accepting it

  • Physics - ,

    The other problems?

    Bainbridge mss spectrometer

    Magnetic Field of a current-carrying ribbon

    Second Rl circuit

    magnetic Field of a loop - Bz.

  • Physics - ,

    I've solved all problems just got stuck with this one...

  • Physics - ,

    Consider a thin, infinitely long conducting ribbon that carries a uniform current density j (current per unit area). The width of the ribbon is w and its thickness s is extremely small (s≪w). P is a point in the plane of the ribbon, at a large distance (x≫s) from the ribbon edge. (See the figure below)

    What is the magnitude of the magnetic field B (in T) at point P for the following values of w , j, s and x?
    w= 8 cm; s= 0.1 cm; j=1A/m2 and x= 22 cm.

    Please help with formula to solve it

  • Physics - ,

    can you share formulas or aproach

  • Physics - ,

    Q:3
    for part a: B=E/v
    for part b: (L^2+h^2)/2L
    for part c: m=rqB/v

  • Physics - ,

    Q6: ((mu_0*I)/2*pi*w)*ln(1+(w/x)) .... (I = J*w*s) and convert cm to m.

  • Physics - ,

    In the circuit shown in the figure below, the switch closes at t=0, R=5.5 Ohm, ε=9 V, L=0.08 H.

    (a) What are the currents (in A) through the two bottom branches at t=0+ (just after the switch is closed)?
    I1 and I2 ?

    (b) What are the currents (in A) through the two bottom branches at a much later time t≈∞?
    I1 and I2 ?

    Please help with the formula

  • Physics - ,

    X10
    Q3 part c and Q6 are wrong could check formulas

  • Physics - ,

    for q3 part c use the Bo not the one derived in part a...and for q6 make sure u have converted the values in m from cm

  • Physics - ,

    Q6: ((mu_0*I)/2*pi*w)*ln(1+(w/x))

    do u divide by 2 * pi * w

  • Physics - ,

    Thanks
    what the formula for Bz in Q5

  • Physics - ,

    X10 are done now

  • Physics - ,

    X10 there must be a problem with the grader as you suggested your friend got the right answer and a friend of mine got the right answer too with the provided formula by Anton.

  • Physics - ,

    In the circuit shown in the figure below, the switch closes at t=0, R=5.5 Ohm, ¦Å=9 V, L=0.08 H.

    (a) What are the currents (in A) through the two bottom branches at t=0+ (just after the switch is closed)?
    I1 and I2 ?

    (b) What are the currents (in A) through the two bottom branches at a much later time t¡Ö¡Þ?
    I1 and I2 ?

    Any the first I1 and last I2 is value 0 both in mine. Any formula to solve the middle ones? I2 and I1

  • Physics - ,

    X10 thanks for your help with Q6:((mu_0*I)/2*pi*w)*ln(1+(w/x)) (I = J*w*s) and convert cm to m.

    I am having issues with the numbers could you check if this is right please?
    If my values are:
    w=8cm; s=0.1cm; j=1A/m(squareroot) and x=22cm
    Is this formula correct:

    I=1*0.1*8=0.8
    ((1.25663706*10^-6*0.8)/2*pi*8)*ln(1+(8/22))

    Thanks X10!

  • Physics - ,

    X10 do you know how to solve for the magnetic field of a loop? i've been cracking my head

  • Physics - ,

    Have same problem like Flu.
    I=1*0.1*8=0.8
    ((1.25663706*10^-6*0.8)/2*pi*8)*ln(1+(8/22))

    This formula did not work, could somebody check it please?
    Thankyou

  • Physics - ,

    Yes, same here, is there an issue with converting it from cm to m maybe? can somebody help where the mistake lie. X10 maybe. thanks!

  • Physics - ,

    it has to be in meters

    I=J*w*s (w and s are in meters so change them)

    then B= (mu_0*(J*w*s))/(2*pi*w)*(ln(1+w/x))

    all are in meters. should get something like a 6.++e-7

  • Physics - ,

    now someone please help me with this question

    A current I=2.9 A flows around a continuous path that consists of portions of two concentric circles of radii a and a/2, respectively, where a=4 cm, and two straight radial segments. The point P is at the common center of the two circle segments.

    stuck. literally

  • Physics - ,

    You don't have any HONOR !!

  • Physics - ,

    Thanks DOnny, did I convert it right?
    I want to be sure, as this is my last try.
    ((1.25663706*10^-6*(1*0.08*0.001))/2*pi*0.08)*ln(1+(0.08/0.22))

    Thanks again.

  • Physics - ,

    Flu our values may vary so i am not certain. but the formulas are fine

    if you could assist me on Q5 Flu ?

  • Physics - ,

    DOnny, I am getting 3.91822*10^-12 and that is marked wrong, could you tell me the full value? 6.++e-7
    please

  • Physics - ,

    DOnny my values are like this below:
    w=8cm; s=0.1cm; j=1A/m(squareroot) and x=22cm

    However, I am uncertain as Saga seems to got a wrong answer.

  • Physics - ,

    Yes, have the same value as Flue but marked wrong when I used the formula. There must be something missing, a bracket maybe? Could somebody check.

  • Physics - ,

    I have only the Bx and By, I assume you have them? it is both 0 with mine. I could not figure Bz out yet but will let you know when I do.

  • Physics - ,

    Sorry DOnny, have accidentally used your username. will let you know about Bz when I have figured it out. but have issues with the last problem still. Cannot figure out where the issue lies even though the numbers are converted to meters now.

  • Physics - ,

    sorry its supposed to be 6.++e-11

    if you have your fx-570MS calculator you should be able to find mu_0 there. don't bother expanding the values

  • Physics - ,

    ((1.256637061e-6)*(1*0.08*0.001))/(2*pi*0.08)*(ln(1+(0.08/0.22))

  • Physics - ,

    Unfortunaley, can only use wolframalpha but that should work.

    Could you help me with figuring this problem out?
    my values are:
    w=8cm; s=0.1cm; j=1A/m(squareroot) and x=22cm

    Is this formula correct:

    ((1.25663706*10^-6*(1*0.08*0.001))/2*pi*0.08)*ln(1+(0.08/0.22))

    If you could help me with this I would eternally be greatful!

  • Physics - ,

    the brackets... BRACKETS

    ((1.25663706*10^-6*(1*0.08*0.001))/2*pi*0.08)*ln(1+(0.08/0.22)) = 3.91822*10^-12


    ((1.25663706e-6)*(1*0.08*0.001))/(2*pi*0.08)*ln(1+(0.08/0.22))= 6.2030986e-11

  • Physics - ,

    Thanks will try out!

  • Physics - ,

    @FLu.. No!!! We have the same values for all the test !!
    And I got it right (carring- ribbon !! Give me the B part of the last problem.. and i give this result..

  • Physics - ,

    DOnny you are a star! It worked after a huge struggle! I will try to figure Bz out and will let you know, if I get something.
    Thanks again!

  • Physics - ,

    Niznkl, thanks I got it now with DOnny's help. Which b part do you mean?

  • Physics - ,

    the problem of the sphere .. the magnetic field at the point p .. is all that I need to finish... we got the same values

  • Physics - ,

    Niznkl, it did not work for me but a friend of mine solved it with this formula provided by Anton so it should work. X10 stated that the friend solved it too. However, there was an issue with ours.
    Use this, it should work and report back: remember I is the value from your answer a) so add that below.
    (I*10^(-7))/(2*(z-R))

    If you are finished could you provide by any chance the formula for second RL circuit problem 4? The first is 0 and last one too. However I could not figure out the middle part for a)I2 and b)I1

    I would appreciate if you could provide the formula.
    thanks

  • Physics - ,

    OH and before I forget the formula for Magnetic field of a loop last part Bz?
    Most of us had difficulties with that, so if you could provide us with the formula, I, DOnny, X10 and others would be greatful.

  • Physics - ,

    magnetic loop is the only one i can't solve

  • Physics - ,

    B=[(2*mu_0)/(3*z^3)]*(R^4)*sigma*omega

  • Physics - ,

    Magnetic field in a loop----
    B= B_1 +B_2
    yo have to calculate 2 magnetic fields for a current negative(see Y axis) ( - ) plus current positive
    For a current I=0.2 and a=6cm
    Bz= 4.7125*10^(-6)

  • Physics - ,

    @Niznkl can you give us the formula that you use to get that result for Bz?

  • Physics - ,

    I need the formulas for Q5 , Q6 and Q7

  • Physics - ,

    A spherical shell of radius R carries a uniform surface charge density (charge per unit area) ƒÐ. The center of the sphere is at the origin and the shell rotates with angular velocity ƒÖ (in rad/sec) around the z-axis (z=0 at the origin). Seen from below, the sphere rotates clockwise. (See the figure below)


    (a) Calculate the magnitude of the total current (in A) carried by the rotating sphere for the following values of ƒÐ, ƒÖ and R:
    ƒÐ= 6 ~10−4C m−2, ƒÖ= 5 rad⋅s−1 and R=1m


    unanswered
    (b) Calculate the magnitude of the magnetic field B(z) (in T) that is generated by the circular current of the rotating shell at a point P on the z-axis for the following values of ƒÐ, ƒÖ , z and R:
    ƒÐ= 6 ~10−4C m−2, ƒÖ= 5 rad⋅s−1, z= 1.9 m and R=1m

    Please answer

  • Physics - ,

    Honor code????

  • Physics - ,

    Niznkl, thanks I seem to have different values for I at least it is, I=0.75 and a=6 cm.
    COuld you give us the formula please so we can calculate it, or maybe a step by step guide? I could not figure it out.
    thanks!

    Anyone have formula for second RL circuit, Problem 4 too?

  • Physics - ,

    Please Niznkl, provide step by step formula with the value so we can calculate with different values! For magnetic field of a loop

  • Physics - ,

    Please formula for magnetic field of a loop last part Bz?

  • Physics - ,

    Correction it is I=0.85 and a=6cm

  • Physics - ,

    Magnetic field of a loop formula for Bz please?

  • Physics - ,

    Yes, how to calculate Bz for different values please?

  • Physics - ,

    Q5:
    mu_0*i/4r where m_0= 4*pi*10^-7 and r=a please convert cm to m

  • Physics - ,

    Thankyou guys...specially that Anonymous person who provided the correct formula for calculating B in the last question and so mid is over now..
    last quest part b: B=[(2*mu_0)/(3*z^3)]*(R^4)*sigma*omega

  • Physics - ,

    honour code breached

  • Physics - ,

    X10 and Anonymous thanks. Could you tell what are the values of z, R, sigma and omega?
    I cannot identify them.

  • Physics - ,

    Thanks guys. Having problems identifying the variables associated with z, R, sigma and omega too. Is that z=I and R=a? What is sigma and omega value please?

  • Physics - ,

    X10 please formula for second RL circuit!
    And the values for omega, sigma, z and R?

  • Physics - ,

    Guys, I think the formula what X10 provided is for last problem on charged sphere not magnetic field of loop. The values can be found on it.

    X10 did you figure out Bz for magnetic field of a loop?

    and anyone for second RL circuit formula please?

  • Physics - ,

    Oh thanks Flu!
    anyone formula for second RL circuit question and formula for Bz magnetic field loop?

  • Physics - ,

    For Bz quest:5
    0
    0
    mu_0*i/4r where m_0= 4*pi*10^-7 and r=a please convert cm to m

  • Physics - ,

    Great thanks X10!
    For Problem 4, second RL Circuit question, could you help with formula?
    I know that first and last are 0 but the middle one I cannot get.

  • Physics - ,

    Thanks X10, Anyone for second RL circuit? formula to calculate

  • Physics - ,

    I've solved RL circuits using circuit simulator software. Anyhow for Q4
    part - a) I1=0,I2=V/(2R+R)
    part - b) I1=V/2R,I2=0

    These formula can be used but I haven't used these..

  • Physics - ,

    Q3 pls!!!

    A Bainbridge mass spectrometer is shown in the figure. A charged particle with mass m, charge |q|=4.8 ×10−19C and speed v=3 ×106 m/s enters from the bottom of the figure and traces out the trajectory shown in the fields shown. The only electric field E=9 ×103 V/m is in the region where the trajectory of the charge is a straight line.

    (a) When the particle is moving through the first (straight-line) segment of its trajectory, what is the magnitude of the magnetic field B in Tesla?

    (b) The charge hits the left wall of the spectrometer at a vertical distance h=0.179 m above where it entered the upper region and a horizontal distance L=0.425 m to the left of where it entered the upper region (see sketch). What is the radius r of the trajectory in m?

    (c) The mass of the particle can be determined using the radius r, the charge q, the speed v, and the magnetic field B0. Using a value of B0=0.4 T, evaluate the mass of the particle in kg. (Note that the magnitude of the field in the curved section, B0, is NOT the same as the magnitude in the straight section, B, found in part a).

  • Physics - ,

    Someone get the last question right using this formula: [(2*mu_0)/(3*z^3)]*(R^4)*sigma*omega ??

  • Physics - ,

    Anonymous, I think that is question 3 and was provided by X10. Just use the below formula, it works I tried.

    Q:3
    for part a: B=E/v
    for part b: (L^2+h^2)/2L
    for part c: m=rqB/v

  • Physics - ,

    Thanks, FLu!

  • Physics - ,

    //electron9.phys.utk.edu/phys513/Modules/module13/problems13.htm

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